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Physics & science

Half-Life Calculator. Solve for any of the four.

Find the remaining amount, initial amount, elapsed time, or half-life from the other three. Pick what you're solving for and the decay formula rearranges itself.

Live calculation

Which value are you missing?

What are you finding? The value you pick becomes the answer; the other three become inputs.
time units
time units Elapsed time and half-life must use the same unit — both in days, both in years, whatever you choose.
Remaining amount 25

Your figures are kept on this device only.

How it works

Half-life describes decay that halves at a constant rate: after one half-life, half the original amount remains; after two, a quarter; after three, an eighth. One equation captures this, and it rearranges four ways depending on what you already know.

remaining = initial × 0.5^(elapsed time ÷ half-life)
initial = remaining × 2^(elapsed time ÷ half-life)
elapsed time = half-life × log₂(initial ÷ remaining)
half-life = elapsed time ÷ log₂(initial ÷ remaining)

This works for anything that decays exponentially at a fixed rate — radioactive isotopes, drug concentration in the body, or any other quantity that loses a constant fraction over each equal time step.

Worked example

100 units of a substance with a 10-day half-life, after 20 days.

Step by step
  1. Divide elapsed time by half-life: 20 ÷ 10 = 2 half-lives.
  2. Halve the initial amount that many times: 100 × 0.5² = 100 × 0.25.

The remaining amount is 25.

Common questions

Does the amount ever reach exactly zero?

Mathematically, no — each half-life only ever removes half of what's left, so the curve approaches zero without ever quite touching it. In practice, once the amount is small enough it's treated as negligible or undetectable.

Can I use this for radiocarbon dating?

Yes — solve for elapsed time using carbon-14's half-life of about 5,730 years, the estimated initial amount, and the amount remaining today.

Why must remaining be less than initial?

This calculator models decay only, where the amount shrinks over time. If the remaining amount isn't smaller than the initial amount, there's no valid decay time or half-life to solve for.